问题描述
我想要的:计算后的结果应该是2个十进制格式。
这是我的代码
let totalNetWeightLocal = 0;
totalNetWeightLocal = totalNetWeightLocal + Number((parseFloat(item.netWeight) * parseInt(item.quantity)).toFixed(2));
问题: 计算有效,但 toFixed() 无效。我得到的结果超过 2 个十进制值。
有人可以帮我吗?
解决方法
您的代码的问题是,.toFixed(2)
的位置错误
您的代码所做的类似于
const fullWeight = parseFloat(item.netWeight) * parseInt(item.quantity)
totalNetWeightLocal = totalNetWeightLocal + fullWeight.toFixed(2));
这意味着,您将两个字符串相加,例如 0 + '10.24'
,即 010.24
。您需要做的是:
// you don’t need Number() here:
const itemWeight = parseFloat(item.netWeight) * parseInt(item.quantity)
totalNetWeightLocal += itemWeight;
totalNetWeightLocal.toFixed(2);
考虑到,您可能有一个可以编写函数的项目列表,如下所示:
const items = [
{ netWeight: '4.53',quantity: '3' },{ netWeight: '20.33',quantity: '10' }
];
const getTotalNetWeightLoal = items => {
const totalNetWeightLocal = items.reduce(
(weight,{ netWeight,quantity }) =>
weight + parseFloat(netWeight) * parseInt(quantity),0
);
return totalNetWeightLocal.toFixed(2);
};
console.log(getTotalNetWeightLoal(items));
,
试试这个代码。您的代码运行良好。
let item = { "netWeight": "5.99498","quantity": '8' }
let totalNetWeightLocal = 0;
totalNetWeightLocal = totalNetWeightLocal + Number((parseFloat(item.netWeight) * parseInt(item.quantity)).toFixed(2));
console.log(totalNetWeightLocal) // output: 47.96
//Can you provide cases where it failed?