问题描述
要仅插入非null:
insert into playlist_genre (playlist_id, genre_id)
select playlist_id, genre_id
from (values
(${playlistid}, ${genre1id}),
(${playlistid}, ${genre2id}),
(${playlistid}, ${genre3id})
) s (playlist_id, genre_id)
where genre_id is not null
解决方法
我有以下查询,将数据插入到多对多联接表中
INSERT INTO playlist_genre(playlist_id,genre_id)
VALUES (${playlistId},${genre1Id}),(${playlistId},${genre2Id}),${genre3Id})
);
但是,我遇到的问题是用户并不需要这些值genre2Id
和genre3Id
,因此可以是anINTEGER
或NULL
。
我正在尝试找到一种方法来写入此相同的查询,但因此仅在存在值的情况下才插入。两列都有NOT NULL
约束。
编辑 :
这是我的播放列表课程
class Playlist {
constructor(playlist) {
// required fields
this.title = playlist.title;
this.playlistType = playlist.playlistType;
this.userId = playlist.userId;
this.numberOfTracks = playlist.numberOfTracks;
this.lengthInSeconds = playlist.lengthInSeconds;
this.genre1Id = playlist.genre1Id;
// not required fields
this.genre2Id = playlist.genre2Id || null;
this.genre3Id = playlist.genre3Id || null;
this.description = playlist.description || null;
this.releaseDate = playlist.releaseDate || null;
}
save() {
return new Promise((resolve,reject) => {
db.one(sqlCreatePlaylist,this)
.then((insertedPlaylist) => {
// Here is where i want to use insertedPlaylist's id
// to insert data into 'playlist_genre' table
resolve(insertedPlaylist);
})
.catch(error => reject(error));
});
}
这是sqlCreatePlaylist的样子
INSERT INTO playlists(
user_id,title,playlist_type,number_of_tracks,duration,description,release_date
)
VALUES(
${userId},${title},${playlistType},${numberOfTracks},${lengthInSeconds},${description},${releaseDate}
)
RETURNING *;