问题描述
通常,您可以将查询的结果(基本上是一个表)插入为另一个查询的FROM子句源,因此将这样编写:
SELECT COUNT(*), SUM(SUBQUERY.AGE) from
(
SELECT availables.bookdate AS Date, DATEDIFF(Now(),availables.updated_at) as Age
FROM availables
INNER JOIN rooms
ON availables.room_id=rooms.id
WHERE availables.bookdate BETWEEN '2009-06-25' AND date_add('2009-06-25', INTERVAL 4 DAY) AND rooms.hostel_id = 5094
GROUP BY availables.bookdate
) AS SUBQUERY
解决方法
我有一个查询:
SELECT availables.bookdate AS Date,DATEDIFF(now(),availables.updated_at) as Age
FROM availables
INNER JOIN rooms
ON availables.room_id=rooms.id
WHERE availables.bookdate BETWEEN '2009-06-25' AND date_add('2009-06-25',INTERVAL 4 DAY) AND rooms.hostel_id = 5094
GROUP BY availables.bookdate
返回如下内容:
Date Age
2009-06-25 0
2009-06-26 2
2009-06-27 1
2009-06-28 0
2009-06-29 0
然后,我该如何对返回的行数进行计数(在这种情况下为5)和年龄的总和?要仅返回带有Count和SUM的一行?
Count SUM
5 3
谢谢