问题描述
select id, avg(amount)
from (select d.*,
min(amount) over (partition by id) as mina,
max(amount) over (partition by id) as maxa
from data d
) d
where amount > mina and amount < maxa
group by id;
解决方法
我的数据类似于以下内容:
Date ID Amount
10-Jun-14 978500302 163005350
17-Jun-14 978500302 159947117
24-Jun-14 978500302 159142342
1-Jul-14 978500302 159623201
8-Jul-14 978500302 143066033
14-Jul-14 978500302 145852027
15-Jul-14 978500302 148595751
甲骨文中有一种方法可以获取此数据的平均值,但不包括最高和最低值吗?我可以通过执行GROUP BY
ID
,然后获得总体平均值AVG(Amount)
。但是如何在排除最小和最大的同时做到这一点呢?