问题描述
这是一个主意(和它有关):
;WITH MoneyComingIn AS
(
SELECT MIN(startdate) AS startdate, MAX(enddate) AS enddate,
SUM(amount) AS amount
FROM myTable
WHERE amount > 0
)
SELECT MIN(startdate) AS startdate, MAX(enddate) AS enddate,
SUM(amount) AS amount
FROM myTable
WHERE enddate < (SELECT startdate FROM MoneyComingIn)
UNION ALL
SELECT startdate, enddate, amount
FROM MoneyComingIn
UNION ALL
SELECT MIN(startdate) AS startdate, MAX(enddate) AS enddate,
SUM(amount) AS amount
FROM myTable
WHERE startdate > (SELECT enddate FROM MoneyComingIn)
第二秒,不使用UNION
(fiddle):
SELECT MIN(startdate), MAX(enddate), SUM(amount)
FROM
(
SELECT startdate, enddate, amount,
CASE
WHEN EXISTS(SELECT 1
FROM myTable b
WHERE b.id>=a.id AND b.amount > 0) THEN
CASE WHEN EXISTS(SELECT 1
FROM myTable b
WHERE b.id<=a.id AND b.amount > 0)
THEN 2
ELSE 1
END
ELSE 3
END AS partition_no
FROM myTable a
) x
GROUP BY partition_no
尽管我认为如所写,但它假定Id
是有序的。您可以用代替它ROW_NUMBER() OVER(ORDER BY startdate)
。
解决方法
我正在尝试对此表进行查询:
Id startdate enddate amount
1 2013-01-01 2013-01-31 0.00
2 2013-02-01 2013-02-28 0.00
3 2013-03-01 2013-03-31 245
4 2013-04-01 2013-04-30 529
5 2013-05-01 2013-05-31 0.00
6 2013-06-01 2013-06-30 383
7 2013-07-01 2013-07-31 0.00
8 2013-08-01 2013-08-31 0.00
我想获得输出:
2013-01-01 2013-02-28 0
2013-03-01 2013-06-30 1157
2013-07-01 2013-08-31 0
我想得到那个结果,所以我会知道什么时候开始赚钱,什么时候停止钱。我还对开始花钱之前的月份数(这解释了第一行)以及停止钱的月份数(这解释了为什么我也对2013年7月至2013年8月的第三行感兴趣)感兴趣。
)。
我知道我可以在日期上使用min和max,在金额上使用sum,但是我不知道如何以这种方式划分记录。
谢谢!