问题描述
试试这个,works on sql-Server 2008.
这是Sql
Fiddle。
请注意,我假设原始字符串中未包含Char(0),因为即使从原始字符串中也可以简单地替换它。
-- I would like to change the following line so it trims trailing null chars
SET @string = CONVERT(VARCHAR(128), @binary)
SET @string = REPLACE(@string, Char(0),'')
解决方法
设想:
我正在将字符串插入二进制字段(CONTEXT_INFO),然后稍后尝试将其拉出并将其转换回字符串。当我这样做时,结果字符串的长度为128,因为它具有结尾的空字符。
例子:
DECLARE @string VARCHAR(128)
DECLARE @binary VARBINARY(128)
SET @string = 'abcdefg'
SET @binary = CONVERT(VARBINARY(128),@string) --0x61626364656667000000...
SET CONTEXT_INFO @binary
SET @binary = CONTEXT_INFO()
-- I would like to change the following line so it trims trailing null chars
SET @string = CONVERT(VARCHAR(128),@binary)
SELECT
@binary AS [binary],DATALENGTH(@binary) AS [binary.Length],--128 as expected
@string AS [string],DATALENGTH(@string) AS [string.Length] --This is 128,but I need it to be 7
问题:
将二进制字段转换为字符串时,如何修剪尾随的空字符?