问题描述
我不确定这是否正是您所需要的,但是它将逐步删除引用的部分…
String quote = "I say: \"I have something to say, \"It's better to burn out then fade away\"\" outloud...";
if (quote.contains("\"")) {
while (quote.contains("\"")) {
int startIndex = quote.indexOf("\"");
int endIndex = quote.lastIndexOf("\"");
quote = quote.substring(startIndex + 1, endIndex);
System.out.println(quote);
}
}
哪个输出…
I have something to say, "It's better to burn out then fade away"
It's better to burn out then fade away
我不知道这是不是在欺骗…
String quote = "I say: \"I have something to say, \"It's better to burn out then fade away\"\" outloud...\"Just in case you don't believe me\"";
String[] split = quote.split("\"");
for (String value : split) {
System.out.println(value);
}
哪个输出…
I say:
I have something to say,
It's better to burn out then fade away
outloud...
Just in case you don't believe me
好,假的 String#split
StringBuilder sb = new StringBuilder(quote.length());
for (int index = 0; index < quote.length(); index++) {
if (quote.charAt(index) == '"') {
System.out.println(sb);
sb.delete(0, sb.length());
} else {
sb.append(quote.charAt(index));
}
}
好吧,这基本上是split
带有选择的假货…
String quote = "blah blah 123 \"hello\" 234 \"world\"";
boolean quoteOpen = false;
StringBuilder sb = new StringBuilder(quote.length());
for (int index = 0; index < quote.length(); index++) {
if (quote.charAt(index) == '"') {
if (quoteOpen) {
System.out.println("Quote: [" + sb.toString() + "]");
quoteOpen = false;
sb.delete(0, sb.length());
} else {
System.out.println("Text: [" + sb.toString() + "]");
sb.delete(0, sb.length());
quoteOpen = true;
}
} else {
sb.append(quote.charAt(index));
}
}
if (sb.length() > 0) {
if (quoteOpen) {
System.out.println("Quote: [" + sb.toString() + "]");
} else {
System.out.println("Text: [" + sb.toString() + "]");
}
}
产生…
Text: [blah blah 123 ]
Quote: [hello]
Text: [ 234 ]
Quote: [world]
知道,我不知道您如何存储结果。我很想创建一些能够存储String
结果并将其添加到a的基本类,List
以便我可以维持顺序,并可能使用某种类型的标志来确定它们是什么类型…
解决方法
我想检索有人作为字符串输入的引号中的任何内容,我假设它是我需要的子字符串,但我不确定如何使用。
当用户输入由单词和数字混合而成的字符串时,它们之间用一个空格隔开:嘿110说“我不太擅长Java”,但“我会很好地钓鱼”
然后,我希望能够采用“我不太擅长Java”和“我能很好地钓鱼”并打印出引号内的内容,以便字符串中可以有多个引号。现在我有if(userInput
==’“”)然后我用子字符串做些什么,但我不确定。
我不能使用split,trim,tokenizer,regex或任何会使此变得非常简单的东西。
在此方法中,所有这些都是我尝试确定字符串中的某些内容是单词,数字还是引号:
public void set(String userInput)// method set returns void
{
num=0;// reset each variable so new input can be passed
String empty="";
String wordBuilder="";
userInput+=" ";
for(int index=0; index<userInput.length(); index++)// goes through each character in string
{
if(Character.isDigit(userInput.charAt(index)))// checks if character in the string is a digit
{
empty+=userInput.charAt(index);
}
else
{
if (Character.isLetter(userInput.charAt(index)))
{
wordBuilder+=userInput.charAt(index);
}
else
{
if(userInput.charAt(index)=='"')
{
String quote=(userInput.substring(index,);
}
}
//if it is then parse that character into an integer and assign it to num
num=Integer.parseInt(empty);
word=wordBuilder;
empty="";
wordBuilder="";
}
}
}
}
谢谢!