我试图在Delphi中获取pidl形式的路径时获得访问冲突,并且返回的pidl为nil.这是我的代码:
type // TParseDisplayName = function(pszPath: PChar; pbc: pointer; var pidl: PItemIDList; sfgaoIn: LongWord; var psfgaoOut: LongWord): LongInt; TParseDisplayName = function(pszPath: PWideChar; pbc: IBindCtx; var pidl: PItemIDList; sfgaoIn: ULong; var psfgaoOut: ULong): HResult; var SHParseDisplayName: TParseDisplayName; SHELL32DLLHandle : THandle; procedure test(); var ws : WideString; tmpLongWord: ULong; lpItemID: PItemIDList; begin //ws := 'Mes documents'; CoInitialize(nil); // path to test ws := 'C:\inetsdk\Nouveau Document WordPad.doc'; if (SHParseDisplayName(PWideChar(ws),nil,lpItemID,tmpLongWord) = S_OK) then if not assigned(lpItemID) then s := SysErrorMessage(getLastError); CoUnInitialize(); end; initialization SHELL32DLLHandle := LoadLibraryW('shell32.dll'); @SHParseDisplayName := GetProcAddress(SHELL32DLLHandle,'SHParseDisplayName');
解决方法
TParseDisplayName的声明省略了调用约定.你需要包括stdcall.
TParseDisplayName = function(pszPath: PWideChar; pbc: IBindCtx; var pidl: PItemIDList; sfgaoIn: ULong; var psfgaoOut: ULong): HResult; stdcall;
如果未指定调用约定,则使用默认调用约定.默认调用约定是register.这对于参数传递和清理具有不同的语义,这导致您遇到的运行时错误类型.实际上所有的Windows API函数都使用了stdcall.