组合CSS第n个子函数

这是我的DOM.我需要选择中间的三列,跳过一个节点,重复：

+-------------------+  <div class="grid">
| +---+ +---+ +---+ |    <div class="cell">1</div>
| | 1 | | 2 | | 3 | |    <div class="cell">2</div>
| +---+ +---+ +---+ |    <div class="cell">3</div>
| +---+ +---+ +---+ |    <div class="cell">4</div>
| | 4 | | 5 | | 6 | |    <div class="cell">5</div>
| +---+ +---+ +---+ |    <div class="cell">6</div>
| +---+ +---+ +---+ |    <div class="cell">7</div>
| | 7 | | 8 | | 9 | |    <div class="cell">8</div>
| +---+ +---+ +---+ |    <div class="cell">9</div>
| +---------------+ |
| |    AD UNIT    | |    <div class="adUnit"></div>
| +---------------+ |
| +---+ +---+ +---+ |    <div class="cell">11</div>
| | 11| |12 | |13 | |    <div class="cell">12</div>
| +---+ +---+ +---+ |    <div class="cell">13</div>
| +---+ +---+ +---+ |    <div class="cell">14</div>
| |14 | |15 | |16 | |    <div class="cell">15</div>
| +---+ +---+ +---+ |    <div class="cell">16</div>
| +---+ +---+ +---+ |    <div class="cell">17</div>
| |17 | |18 | |19 | |    <div class="cell">18</div>
| +---+ +---+ +---+ |    <div class="cell">19</div>
| +---------------+ |
| |    AD UNIT    | |    <div class="adUnit"></div>
| +---------------+ |
| +---+ +---+ +---+ |    <div class="cell">21</div>
| |21 | |22 | |23 | |    <div class="cell">22</div>
| +---+ +---+ +---+ |    <div class="cell">23</div>
| +---+ +---+ +---+ |    <div class="cell">24</div>
| |24 | |25 | |...| |    <div class="cell">25</div>
| +---------------+ |    <!-- ... -->
+-------------------+  </div>

tldr

我需要选择以下序列[children节点]：

2,5,8,12,15,18,22,25,28,32,35,38,...

我已经实现了三个独立的第n个孩子的功能：

> .grid .cell：nth-​​child(10n 2)(2,…)
> .grid .cell：nth-​​child(10n 5)(5,…)
> .grid .cell：nth-​​child(10n 8)(8,…)

题：

这三个功能是否可以重写成一个？

解决方法

事实证明,没有办法使用第n个孩子或第n个类型来做你以后的类型,看你选择什么类型的元素,而不是类.

如果您可以更改广告单元的元素类型,可以使用第n种类型,例如：

<div class="cell">1</div>
<aside class="adUnit"></aside>
<div class="cell">2</div>

如果你可以做出这个改变,那么第n个类型应该允许你定位你的div而不是asides,例如：

.grid > div.cell:nth-of-type(3n+2) { }

编辑：根据web-tiki的评论调整选择器.