c# – 无法反序列化数组

从客户端发送的数据不会反序列化.

客户：

$.ajax({
     type: 'POST',dataType: "json",url: 'savecommentsservice',data: { "Pid": 0,"Comments": [{ "User": "bbbbbb","Text": "aaaaaaaa" },{ "User": "ddddddd","Text": "ccccccccc"}] },

DTO：

public class Comment
{
    public string User { get; set; }
    public string Text { get; set; }
}
public class SaveCommentsRequest
{
    public int Pid { get; set; }
    public string SiteId { get; set; }
    public string Column { get; set; }
    public List<Comment> Comments { get; set; }
}

服务器：

Routes.Add<SaveCommentsRequest>("/savecommentsservice");

...

public object Execute(SaveCommentsRequest request)
    {
        // Why is request.Comments null !!! All other params of the request works fine

        // THe string I'm putting in is generated below - just to make sure its correct
        request.Comments = new List<Comment>();
        request.Comments.Add(new Comment { Text = "aaaaaaaa",User = "bbbbbb" });
        request.Comments.Add(new Comment { Text = "ccccccccc",User = "ddddddd" });

        var thisIsWhatIPutInto$AjaxCall = JsonSerializer.SerializetoString<SaveCommentsRequest>(request);

任何想法有什么不对？为什么没有填充Comments数组.正如您从注释中看到的那样,我使用servicestack json序列化器生成了字符串.

也许我在这里想念一些？

编辑
当看到小提琴手传来的时候,我看到了这个：

POST http://localhost:4920/savecommentsservice HTTP/1.1
Host: localhost:4920
User-Agent: Mozilla/5.0 (Windows NT 5.1; rv:10.0.2) Gecko/20100101 Firefox/10.0.2
Accept: application/json,text/javascript,*/*; q=0.01
Accept-Language: zh,en-us;q=0.7,en;q=0.3
Accept-Encoding: gzip,deflate
Connection: keep-alive
Content-Type: application/x-www-form-urlencoded; charset=UTF-8
X-Requested-With: XMLHttpRequest
Referer: http://localhost:4920/default.cshtml?viewId=3
Content-Length: 227
Cookie: ASP.NET_SessionId=slbw453revfgmwuuxyrim1an
Pragma: no-cache
Cache-Control: no-cache

SiteId=Site1&Pid=0&Column=C6&Comments%5B0%5D%5BUser%5D=bbbbbb&Comments%5B0%5D%5BText%5D=aaaaaaaa&Comments%5B1%5D%5BUser%5D=ddddddd&Comments%5B1%5D%5BText%5D=ccccccccc&Comments%5B2%5D%5BUser%5D=ggggggg&Comments%5B2%5D%5BText%5D=

在萤火虫：

Parametersapplication/x-www-form-urlencoded
Column  C6
Comments[0][Text]   aaaaaaaa
Comments[0][User]   bbbbbb
Comments[1][Text]   ccccccccc
Comments[1][User]   ddddddd
Comments[2][Text]   
Comments[2][User]   ggggggg
Pid 0
SiteId  SiteId0
Source
SiteId=SiteId0&Pid=0&Column=C6&Comments%5B0%5D%5BUser%5D=bbbbbb&Comments%5B0%5D%5BText%5D=aaaaaaaa&Comments%5B1%5D%5BUser%5D=ddddddd&Comments%5B1%5D%5BText%5D=ccccccccc&Comments%5B2%5D%5BUser%5D=ggggggg&Comments%5B2%5D%5BText%5D=

问候

larsi

解决方法

正如您在默认情况下所看到的,jQuery的Ajax将其提交为“application / x-www-form-urlencoded”,这是默认的HTML Form Post Content-Type.不幸的是,它不能很好地处理嵌套对象,而ServiceStack将期望 JSV Format中的嵌套对象.

因此,对于复杂类型/嵌套对象,您希望告诉jQuery将请求作为JSON发送,您可以通过指定contentType：application / json参数来执行此操作,例如：

var data = { "Pid": 0,"Text": "aaaaaaaa" }]};
$.ajax({
     type: 'POST',contentType: "application/json",data: JSON.stringify(data)
);