c# – XmlSerializer生成没有命名空间前缀的XML

我必须创建一个前缀为所有元素的 XML文件,如下所示:
<ps:Request num="123" xmlns:ps="www.ladieda.com">
   <ps:ClientId>5566</ps:ClientId>
<ps:Request>

当我序列化我的对象时,c#很聪明并且这样做:

<Request num="123" xmlns="www.ladieda.com">
   <ClientId>5566</ClientId>
<Request>

这很好,因为ps:不是必需的.

但有没有办法强制C#序列化所有前缀?

我的序列化代码是这样的(对于传入的对象pObject):

String XmlizedString = null;
MemoryStream memoryStream = new MemoryStream();
XmlSerializer xs = new XmlSerializer(pObject.GetType());
XmlTextWriter xmlTextWriter = new XmlTextWriter(memoryStream,Encoding.UTF8);

xs.Serialize(xmlTextWriter,pObject);
memoryStream = (MemoryStream)xmlTextWriter.BaseStream;
XmlizedString = UTF8ByteArrayToString(memoryStream.ToArray());
return XmlizedString;


private String UTF8ByteArrayToString(Byte[] characters)
{
    UTF8Encoding encoding = new UTF8Encoding();
    String constructedString = encoding.GetString(characters);
    return (constructedString);
}

解决方法

首先,如果您的字符串的使用者正在处理XML,那么他们就不会关心前缀,因为它与XML无关.也许他们不理解XML,并认为他们正在处理一个字符串(可能需要在每个元素上都有字符串“ps:”).

其次,您应该稍微更改一下代码

XmlSerializer xs = new XmlSerializer(pObject.GetType());
using (MemoryStream memoryStream = new MemoryStream())
{
    XmlWriterSettings settings = new XmlWriterSettings()
    {
        Encoding = Encoding.UTF8
    };
    using (XmlWriter writer = XmlWriter.Create(memoryStream,settings))
    {
        xs.Serialize(writer,pObject);
    }
    return Encoding.UTF8.GetString(memoryStream.ToArray());
}

如果抛出异常,这将正确处理流和XmlWriter,停止使用已弃用的XmlTextWriter类,但仍返回包含为UTF-8编写的XML的字符串.

最后,要控制前缀,请参阅“How to: Qualify XML Element and XML Attribute Names”

XmlSerializerNamespaces myNamespaces = new XmlSerializerNamespaces();
myNamespaces.Add("ps","www.ladieda.com");

XmlSerializer xs = new XmlSerializer(pObject.GetType());
using (MemoryStream memoryStream = new MemoryStream())
{
    XmlWriterSettings settings = new XmlWriterSettings()
    {
        Encoding = Encoding.UTF8
    };
    using (XmlWriter writer = XmlWriter.Create(memoryStream,pObject,myNamespaces);
    }
    return Encoding.UTF8.GetString(memoryStream.ToArray());
}

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