我有一个类,我想将
XML-doc反序列化为:
[XmlRoot(ElementName = "MyType",Namespace = "MyNamespace")] public class MyClass : MyBase { }
和
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd","2.0.50727.42")] [SerializableAttribute()] [System.ComponentModel.DesignerCategoryAttribute("code")] [XmlTypeAttribute(Namespace = "BaseNamespace")] [XmlRootAttribute("MyBaseType",Namespace = "BaseNamespace",IsNullable = false)] [GuidAttribute("8d9586ec-f263-48e2-ad47-53093430bce4")] public class MyBase { }
XML schema file with Metadata not found at AAA-Fachschema.xsd”:null
这是一些简化的Xml:
<?xml version="1.0" encoding="utf-8"?> <!--some comments --> <q1:MyType xsi:schemaLocation="http://www.adv-online.de/namespaces/adv/gid/6.0 NAS-Operationen.xsd" xmlns:q1="MyNamespace" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:gml="http://www.opengis.net/gml/3.2" xmlns:xlink="http://www.w3.org/1999/xlink" xmlns:gco="http://www.isotc211.org/2005/gco" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:gts="http://www.isotc211.org/2005/gts" xmlns:ogc="http://www.adv-online.de/namespaces/adv/gid/ogc" xmlns:wfs="http://www.adv-online.de/namespaces/adv/gid/wfs" xmlns:gss="http://www.isotc211.org/2005/gss" xmlns="BaseNamespace"> </q1:MyType>
并且代码反序列化:
using (var reader = new XmlReader(theFile,new XmlReaderSettings { ValidationType = ValidationType.None })) { var ser = new XmlSerializer(typeof(MyClass)); var o = ser.Deserialize(reader); }
但我完全不确定这个Xsd文件设置为由序列化程序加载的位置.
有谁知道在哪里为序列化器设置这些信息,甚至更简单的如何完全禁用检查?