我有几个线程,我需要抓住他们都完成工作的那一刻.
怎么做?
怎么做?
for (int i = 1; i < 3; i++) { std::thread threads1(countFile,i); i++; std::thread threads2(countFile,i); threads1.detach(); threads2.detach(); } // wait until all the threads run out--- // to do next function ob object which uses by threads--
解决方法
考虑在for-block之外创建std :: thread对象并调用join()而不是detach():
// empty (no threads associated to them yet) std::array<std::thread,2> threads1,threads2; for (int i = 0; i < 2; i++) { threads1[i] = std::thread(countFile,i+1); // create thread i++; threads2[i] = std::thread(countFile,i+1); // create thread } // ... // join on all of them for (int i = 0; i < 2; i++) { threads1[i].join(); threads2[i].join(); } // at this point all those threads have finished
不调用detach()意味着必须在调用std :: thread对象的析构函数之前调用join()(无论线程是否已经完成).
出于这个原因,我将std :: thread对象放在for-block之外.否则,必须在for-block内调用join().