c – 共享库中模板类和dynamic_cast的显式实例化

我今天陷入困境,似乎无法解决.我正在编译一个共享库,其中包含一个模板类(Derived< T>,其基础是Base)和这个类的某些显式实例.我希望图书馆用户从这个模板类扩展.当我尝试将用户的实例从Base *动态化为Derived< T> *时,会出现此问题.

我把问题缩小到了这个MWE：

共享库包含以下文件：

Base.h

#ifndef BASE_H_
#define BASE_H_

class Base {
public:
    Base();
    virtual ~Base();
};

#endif /* BASE_H_ */

Derived.h

#ifndef DERIVED_H_
#define DERIVED_H_    
#include <Base.h>

template <typename T>
class Derived : public Base {
public:  
    Derived();
    virtual ~Derived();
};

#endif /* DERIVED_H_ */

Derived.cpp

#include <Derived.h>

template <typename T>
Derived<T>::Derived() :
    Base() {
}

template <typename T>
Derived<T>::~Derived() {
}

// explicit instantiations
template class Derived<float>;
template class Derived<double>;
template class Derived<long double>;

Helper.h

#ifndef HELPER_H_
#define HELPER_H_

#include <Base.h>

class Helper {
public:
    Helper(Base* m);
    virtual ~Helper();

};

#endif /* HELPER_H_ */

Helper.cpp

#include <Helper.h>
#include <Base.h>
#include <Derived.h>

#include <iostream>

using namespace std;

Helper::Helper(Base* m) {

    cout << "after received " << m << endl;
    cout << "after fom: " <<  dynamic_cast< Derived<float>* >(m) << endl;
    cout << "after dom: " <<  dynamic_cast< Derived<double>* >(m) << endl;
    cout << "after ldom: " <<  dynamic_cast< Derived<long double>* >(m) << endl;
    cout << "===" << endl;
}

Helper::~Helper() {
}

而使用该库的简单代码可以是：

TEST.CPP

#include <Derived.h>
#include <Helper.h>

#include <iostream>

using namespace std;

class MyModel : public Derived<double> {
public:
    MyModel() : Derived<double>() {
    };

    virtual ~MyModel() {
    };        

};

int main(int argc,char *argv[]) {

    MyModel om1;
    cout << "created mymodel " << &om1 << endl;
    cout << "before fom: " <<  dynamic_cast< Derived<float>* >(&om1) << endl;
    cout << "before dom: " <<  dynamic_cast< Derived<double>* >(&om1) << endl;
    cout << "before ldom: " <<  dynamic_cast< Derived<long double>* >(&om1) << endl;
    cout << "===" << endl;
    Helper root(&om1);

    return 0;
}

问题是当我创建一个共享库并链接test.cpp时,dynamic_cast将失败.以下是一个示例输出：

created mymodel 0x7fff5fbff3e0
before fom: 0
before dom: 0x7fff5fbff3e0
before ldom: 0
===
after received 0x7fff5fbff3e0
after fom: 0
after dom: 0  // <<< Here I expected it to succeed and return a non-null pointer
after ldom: 0
===

但是,如果我将整个库和示例一起编译,则转换成功：

created mymodel 0x7fff5fbff3e0
before fom: 0
before dom: 0x7fff5fbff3e0
before ldom: 0
===
after received 0x7fff5fbff3e0
after fom: 0
after dom: 0x7fff5fbff3e0
after ldom: 0
===

我的问题是：为什么dynamic_cast失败？

而且,在我想维护一个类结构的前提下,我们要继续使用一个共享库：如何从Base *中成功获取Derived< some type> * cast？

解决方法

我假设你在Linux / GCC上,因为在Windows上它应该“只是工作”.

它不与GCC“正常工作”,因为GCC中的性能RTTI支持依赖于指针比较.这一切都在this GCC FAQ年解释,包括如何解决.编辑：虽然,这个FAQ表示它不适用于dlopen(),而显式链接到共享库应该工作;所以也许还有别的东西,比如下面提到的bug.

我发现一些其他链接可以帮助：
dynamic_cast an interface from a shared library which was loaded by lt_dlopen(libtool) doesn’t work
dynamic cast with interfaces
C++ dynamic_cast bug in Mac OS 10.6 Snow Leopard