C函数指针语法

我的问题很简单.

通常,当声明一些变量时,您将其类型放在它之前,如：

int a;

函数指针可能具有类型：int(*)(int,int),以防万一我们指向一个使用两个int并返回int的函数.但是,当声明这样的指针时,它的标识符不在类型之后,如：

int(*)(int,int) mypointer;

相反,您必须在中间写入标识符：

int(*mypointer)(int,int);

为什么这样呢？
对不起,我知道这是一个令人尴尬的简单问题

感谢大家的回复.
如.

解决方法

我在 Why was the C syntax for arrays,pointers,and functions designed this way?的答复中解释一下,基本上归结为：

the language authors preferred to make the Syntax variable-centric rather than type-centric. That is,they wanted a programmer to look at the declaration and think “if I write the expression *func(arg),that’ll result in an int; if I write *arg[N] I’ll have a float” rather than “func must be a pointer to a function taking this and returning that“.

The 07001 claims that:

Ritchie’s idea was to declare identifiers in contexts resembling their use: “declaration reflects use”.

…citing p122 of K&R2.