鉴于：
template <typename T>
class C {
C & operator ++ () { ... }
};
为什么/如何允许C声明类型C的变量和函数而不是命名C< T>？在使用许多参数来模拟“自我类型”不方便的模板之前,我还没有真正考虑过它.
我应该知道这有什么怪癖吗？
解决方法
[n3290: 14.6.1/1]:Like normal (non-template) classes,class
templates have an injected-class-name (Clause 9). The
injected-class-name can be used as a template-name or a type-name.
When it is used with a template-argument-list,as a
template-argument for a template template-parameter,or as the final identifier in the elaborated-type-specifier of a friend class
template declaration,it refers to the class template itself.
Otherwise,it is equivalent to the template-name followed by the
template-parameters of the class template enclosed in<>.
