题意:N!的位数
思路:log10的使用,log10(1*2*3*4........*n) = log10(1) + log10(2)+.............
#include<iostream> #include<cstring> #include<cstdio> #include<cmath> using namespace std; int main() { int t; scanf("%d",&t); while(t--) { int n = 0; double sum = 0; scanf("%d",&n); for(int i = 1;i <= n; i++) { sum = sum + log10(i); } printf("%.0lf\n",sum+0.5); } return 0; }