Big Number
Problem Description
As we kNow,Big Number is always troublesome. But it's really important in our ACM. And today,your task is to write a program to calculate A mod B.
To make the problem easier,I promise that B will be smaller than 100000.
Is it too hard? No,I work it out in 10 minutes,and my program contains less than 25 lines.
To make the problem easier,I promise that B will be smaller than 100000.
Is it too hard? No,I work it out in 10 minutes,and my program contains less than 25 lines.
Input
The input contains several test cases. Each test case consists of two positive integers A and B. The length of A will not exceed 1000,and B will be smaller than 100000. Process to the end of file.
Output
For each test case,you have to ouput the result of A mod B.
Sample Input
2 3 12 7 152455856554521 3250
Sample Output
2 5 1521
...直接代码
#include <iostream> using namespace std; int main() { char s[1111]; int b,i; while(scanf("%s%d",s,&b)!=EOF) { int mod=0; for(i=0;i<strlen(s);i++) { mod=mod*10+s[i]-'0'; mod%=b; } printf("%d\n",mod); } return 0; }