N!
Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 53495 Accepted Submission(s): 15120
Problem Description
Given an integer N(0 ≤ N ≤ 10000),your task is to calculate N!
Input
One N in one line,process to the end of file.
Output
For each N,output N! in one line.
Sample Input
1 2 3
Sample Output
1 2 6
Author
JGShining(极光炫影)
题目大意:计算大数的阶乘
要点:数组开大些,,,,,又开小了,wa了一次
ac代码
#include<stdio.h> int main() { int n; while(scanf("%d",&n)!=EOF) { int i,a[100200],c,d=1,tc,j; a[1]=1; for(i=1;i<=n;i++) { for(j=1,c=0;j<=d;j++) { tc=a[j]*i+c; a[j]=tc%10; c=tc/10; } while(c) { a[++d]=c%10; c/=10; } } for(i=d;i>=1;i--) printf("%d",a[i]); printf("\n"); } }