A == B ?
Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 73311 Accepted Submission(s): 11575
Problem Description
Give you two numbers A and B,if A is equal to B,you should print "YES",or print "NO".
Input
each test case contains two numbers A and B.
Output
for each case,or print "NO".
Sample Input
1 2 2 2 3 3 4 3
Sample Output
NO YES YES NO
完美AC代码如下:
#include<stdio.h> #include<stdlib.h> #include<string.h> #define MAX 100100//数组一定要开足够大,因为开小了,WA了两次 char str1[MAX],str2[MAX]; void cleanzero(char str[]) { int len,i; len=strlen(str); if(strstr(str,"."))//去除后导零及不跟小数位的后导小数点 { for(i=len-1;str[i]=='0';i--) str[i]='\0'; if(str[i]=='.') str[i]='\0'; } if(str[0]=='0')//去除前导零 { while(str[0]=='0') { for(i=0;i<len-1;i++) str[i]=str[i+1]; str[len-1]='\0'; len--; } } } int main() { while(scanf("%s%s",str1,str2)!=EOF) { cleanzero(str1); cleanzero(str2); if(strcmp(str1,str2))//比较两个字符 printf("NO\n"); else printf("YES\n"); } return 0; }