如何返回到源代码的bash脚本？

我使用一个脚本扩展使用bash源功能;

#!/bin/bash

source someneatscriptthatendsprematurely.sh

我想能够从那个脚本返回，而不破坏主脚本。

使用退出断点的主脚本，返回只在函数中有效，并尝试$(退出1)似乎也不工作。

那么，是否可以返回一个sub-bash脚本而不打破主bash？

任何帮助赞赏！

你需要return语句：

return [n]
Causes a function to exit with the return value specified by n. If n is omitted,the return status is that of the last command executed in the function body. If used outside a function,but during execution of a script by the . (source) command,it causes the shell to stop executing that script and return either n or the exit status of the last command executed within the script as the exit status of the script. If used outside a function and not during execution of a script by .,the return status is false. Any command associated with the RETURN trap is executed before execution resumes after the function or script.

您可以使用以下两个脚本查看此操作：

script1.sh:
    . script2.sh
    echo hello again
script2.sh:
    echo hello
    return
    echo goodbye

当您运行script1.sh时，您会看到：

hello
hello again