shell – 使用cURL登录堆栈溢出

我正在开发一个项目,我想通过cURL登录到Stack Overflow.

我使用Google作为我的openID提供程序,这意味着我需要先通过其API登录Google.

以下是我到目前为止的代码：

#!/bin/sh
. ./params.sh #the script with $username and $password
curl --silent https://www.google.com/accounts/ClientLogin \
-d Email=$username -d Passwd=$password \
-d accountType=GOOGLE \
-d source=localhost-test-1 \
-d service=lso \
-o tokens
. ./tokens
echo $Auth; #$Auth is correct here - I did not get a BadAuth error.

endpoint="https://www.google.com/accounts/o8/id";

curl https://stackoverflow.com/users/authenticate \
    -d "openid_identifier=$endpoint" \
    -w %{redirect_url}> ./google_url
google_url=$(cat ./google_url);
echo $google_url;
echo;
echo;
echo;
curl -L --silent --header "Authorization: GoogleLogin auth=$Auth" $google_url;

在这一点上,我收到一个来自Google的页面,告诉我Stack Overflow需要信息,我必须登录.根据this page,-header … $Auth部分应该作为登录名,并将其重定向到Stack Overflow.

这是我运行这个脚本时得到的形式：

<form id="gaia_universallogin"
      action="https://www.google.com/accounts/ServiceLoginAuth?service=lso" method="post">
  <input type="hidden" name="continue" id="continue"
           value="https://www.google.com/accounts/o8/ud?st=SOME_KEY" />
  <input type="hidden" name="service" id="service"
           value="lso" />
  <input type="hidden" name="dsh" id="dsh"
           value="SOME_NEG_NUMBER" />
</form>

当我尝试下面的答案我得到以下错误：

Can't call method "attr" on an undefined value at - line 8.
    curl: (3) <url> malformed
--></style>

这是google2.html的输出

<form id="gaia_loginform"      
        action="https://www.google.com/accounts/ServiceLoginAuth?service=lso" method="post"                >
  <input type="hidden" name="continue" id="continue"            value="https://www.google.com/accounts/o8/ud?st=RNADOM" />
  <input type="hidden" name="service" id="service"            value="lso" />
  <input type="hidden" name="dsh" id="dsh"            value="NEG_NUMEBER" />
  <input type="hidden"              name="galX"             value="ABCD" />
  <input type="text" name="Email"  id="Email" />
  <input type="password"   name="Passwd" id="Passwd" > 
  <input type="checkBox" name="PersistentCookie" id="PersistentCookie"    value="yes"
  <input type="hidden" name='rmShown' value="1" />
  <input type="submit" class="gaia le button" name="signIn" id="signIn"                 />
<input type="hidden" name="asts"    >
</form>

Google登录服务是针对您使用的特定服务(Google文档与Google Analytics(分析)和Google地图等)).您指定的服务(lh2)特定于Google Picasa.

不幸的是,似乎没有OpenID的等效代码(至少不是我可以找到！)

从Google回来的页面应该包含一个登录表单.如果你看这个,应该可以构建卷曲调用来登录;那么应该将您重定向到SO(或您要登录的任何OpenID页面)登录.

事实证明,这样做有点棘手,因为您必须解析出一些表单域才能将其提交回Google,因为Google不会发回直接的HTTP重定向,而是发送带有< ; Meta http-equiv =“redirect”...>标签.当然,您必须启用Cookie.但是这在使用curl的脚本中是可能的 – 以下内容适用于我：

#!/bin/bash

# Utility function for parsing values out of an HTML form
get_value()
{
    local tagtype="$1" attrname="$2" attrvalue="$3" getattr="$4"
    perl -MHTML::TreeBuilder - "$@" <<EOF
         @args=@ARGV;
         \$h=HTML::TreeBuilder->new;
         \$h->parse_file("$htmlfile");
         while (\$#args > 0) {
             \$h=\$h->look_down(_tag => shift @args,shift @args => shift @args);
         }
         print \$h->attr(shift @args);
EOF
}

# Empty the cookie jar
cj="cookiejar"
rm -f "$cj"

# Attempt to log in to SO. This will redirect to a google URL.
endpoint="https://www.google.com/accounts/o8/id"

google_url=`curl -L -s -S https://stackoverflow.com/users/authenticate \
    -d "openid_identifier=$endpoint" \
    -o /dev/null -b "$cj" -c "$cj" \
    -w %{url_effective}`
echo $google_url
echo
echo

# Retrieve the form from Google
htmlfile=googleform.html
curl -L -s -S -o "$htmlfile" -b "$cj" -c "$cj" "$google_url"

# Parse out the form fields
form_url=`get_value form id gaia_loginform action`

fdsh=`get_value form id gaia_loginform input name dsh value`
fcontinue=`get_value form id gaia_loginform input name continue value`
fservice=`get_value form id gaia_loginform input name service value`
fgalX=`get_value form id gaia_loginform input name galX value`
frmShown=`get_value form id gaia_loginform input name rmShown value`
fsignIn=`get_value form id gaia_loginform input name signIn value`

fEmail='INSERT LOGIN EMAIL HERE'
fPasswd='INSERT PASSWORD HERE'

# Submit the login form
htmlfile=google2.html
curl -L -s -S -o "$htmlfile" -b "$cj" -c "$cj" --data-urlencode dsh="$fdsh" \
  --data-urlencode continue="$fcontinue" \
  --data-urlencode service="$fservice" \
  --data-urlencode galX="$fgalX" \
  --data-urlencode Email="$fEmail" \
  --data-urlencode Passwd="$fPasswd" \
  --data-urlencode rmShown="$frmShown" \
  --data-urlencode signIn="$fsignIn" \
  "$form_url"

# Interpret the redirect
redirect=`get_value Meta http-equiv refresh content | sed "s/^.*'\(.*\)'.*$/\1/"`

# Follow it
htmlfile=google3.html
curl -L -s -S -o "$htmlfile" -b "$cj" -c "$cj" "$redirect"

(请注意,我似乎有一个略微不同的卷曲版本,所以我不得不稍微改变-w选项;我猜我的版本会适合你,但你可能需要调整它.)