asp.net – 如何将HttpRequestBase转换为HttpRequestMessage,考虑标题名称？

我将HttpRequestBase包装为HttpRequestMessage,它需要复制所有标头.但由于HttpRequestMessage特别关于哪些头应用于请求对象与Content对象,因此下面的httpRequest.Headers.Add行有时会抛出InvalidOperationException.

public static HttpRequestMessage AsHttpRequestMessage(this HttpRequestBase request) {
    Requires.NotNull(request,"request");

    var httpRequest = new HttpRequestMessage(new HttpMethod(request.HttpMethod),request.Url);
    foreach (string header in request.Headers) {
        httpRequest.Headers.Add(header,request.Headers.GetValues(header));
    }

    if (request.Form != null) {
        // Avoid a request message that will try to read the request stream twice for already parsed data.
        httpRequest.Content = new FormUrlEncodedContent(request.Form.AsKeyValuePairs());
    } else if (request.InputStream != null) {
        httpRequest.Content = new StreamContent(request.InputStream);
    }

    return httpRequest;
}

显然,我希望我的代码不会抛出异常,而是将每个标头适当地应用于适当的对象.我怎么预测呢？我是否可以使用任何方法来测试标题的适用性,而不是生成和捕获异常的标题？

解决方法

事实证明这很简单.这个片段的灵感源自 ASP.NET’s own open sourced source code.

/// <summary>
/// Clones an <see cref="HttpWebRequest" /> in order to send it again.
/// </summary>
/// <param name="message">The message to set headers on.</param>
/// <param name="request">The request with headers to clone.</param>
internal static void CopyHeadersFrom(this HttpRequestMessage message,HttpRequestBase request) {
    Requires.NotNull(request,"request");
    Requires.NotNull(message,"message");

    foreach (string headerName in request.Headers) {
        string[] headerValues = request.Headers.GetValues(headerName);
        if (!message.Headers.TryAddWithoutValidation(headerName,headerValues)) {
            message.Content.Headers.TryAddWithoutValidation(headerName,headerValues);
        }
    }
}