android – 如何在几秒钟不活动后关闭对话框？

我有一个包含对话框的应用程序

我希望在x秒之后关闭此对话框,此时用户没有与应用程序进行任何交互,例如音量搜索栏弹出窗口(单击音量按钮时打开,并且在2秒钟不活动后关闭).
实现这个的最简单方法是什么？

谢谢

解决方法

例如,每次用户与对话框交互时,您都可以使用Handler并调用其.removeCallbacks()和.postDelayed()方法.

在进行交互时,.removeCallbacks()方法将取消.postDelayed()的执行,之后,你将使用.postDelayed()启动一个新的Runnable

在此Runnable中,您可以关闭对话框.

// a dialog
    final Dialog dialog = new Dialog(getApplicationContext());

    // the code inside run() will be executed if .postDelayed() reaches its delay time
    final Runnable runnable = new Runnable() {

        @Override
        public void run() {
            dialog.dismiss(); // hide dialog
        }
    };

    Button interaction = (Button) findViewById(R.id.bottom);

    final Handler h = new Handler();

            // pressing the button is an "interaction" for example
    interaction.setonClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {


            h.removeCallbacks(runnable); // cancel the running action (the hiding process)
            h.postDelayed(runnable,5000); // start a new hiding process that will trigger after 5 seconds
        }
    });

要跟踪用户互动,您可以使用：

@Override
public void onUserInteraction(){
    h.removeCallbacks(runnable); // cancel the running action (the hiding process)
    h.postDelayed(runnable,5000); // start a new hiding process that will trigger after 5 seconds
}

您的活动中有哪些内容.