android – 服务和BroadCastReceiver

我已经看到了如何实现broadCastReceiver的几个例子,但是我应该如何实现必须对一些待处理的Intent(例如来电)做出反应的服务…
其实我是想知道同样的“问题”,但在一个活动..
你显然有一个扩展一个服务或活动的类),因此它不能扩展broadCastReceiver …
看起来我们不能使“平台感知”服务和/或活动？

解决方法

要注册一个活动以获得某种意图,您需要：

// Flag if receiver is registered 
private boolean mReceiversRegistered = false;

// I think this is the broadcast you need for something like an incoming call
private String INCOMING_CALL_ACTION = "android.intent.action.PHONE_STATE";

// Define a handler and a broadcast receiver
private final Handler mHandler = new Handler();
private final broadcastReceiver mIntentReceiver = new broadcastReceiver() {
  @Override
  public void onReceive(Context context,Intent intent) {
    // Handle reciever
    String mAction = intent.getAction();

    if(mAction.equals(INCOMING_CALL_ACTION) {
      // Do your thing   
    }
}

@Override
protected void onResume() {
  super.onResume();

  // Register Sync Recievers
  IntentFilter intentToReceiveFilter = new IntentFilter();
  intentToReceiveFilter.addAction(INCOMING_CALL_ACTION);
  this.registerReceiver(mIntentReceiver,intentToReceiveFilter,null,mHandler);
  mReceiversRegistered = true;
}

@Override
public void onPause() {
  super.onPause();

  // Make sure you unregister your receivers when you pause your activity
  if(mReceiversRegistered) {
    unregisterReceiver(mIntentReceiver);
    mReceiversRegistered = false;
  }
}

那么您还需要在清单中添加意图过滤器：

<activity android:name=".MyActivity" android:label="@string/name" >
   <intent-filter> 
     <action android:name="android.intent.action.PHONE_STATE" /> 
   </intent-filter>
 </activity>