String nom = db.execsql("select name from person where id='+id+'");
任何人都可以纠正我这一行,以获得表人的姓名
解决方法:
如果您的id是整数数据类型,请尝试此操作.
public String getResult(int id)
{
String name = null;
try
{
Cursor c = null;
c = db.rawQuery("select name from person where id="+id, null);
c.movetoFirst();
name = c.getString(c.getColumnIndex("name"));
c.close();
}
catch(Exception e)
{
e.printstacktrace();
}
return name;
}
如果您的id是String数据类型,请尝试此操作.
public String getResult(String id)
{
String name = null;
try
{
Cursor c = null;
c = db.rawQuery("select name from person where id=" + "\""+id+"\"", null);
c.movetoFirst();
name = c.getString(c.getColumnIndex("name"));
c.close();
}
catch(Exception e)
{
e.printstacktrace();
}
return name;
}