我发现这个code通过按下电源按钮启动应用程序.
而且我不知道为什么这段代码对我不起作用,但无论如何我要放一些带清单的代码,请检查……
并告诉我,通过单击或两次按下电源按钮启动应用程序是否正确?
toast = Toast.makeText(getApplicationContext(), "", Toast.LENGTH_SHORT);
btnToggleLock.setonClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
if (btnToggleLock.isChecked()) {
toast.cancel();
toast.setText("Unlocked");
toast.show();
Log.i("Unlocked", "If");
Context context = getApplicationContext();
KeyguardManager _guard = (KeyguardManager) context
.getSystemService(Context.KEyguard_SERVICE);
KeyguardLock _keyguardLock = _guard
.newKeyguardLock("KeyguardLockWrapper");
_keyguardLock.disableKeyguard();
PanicButtonActivity.this.startService(new Intent(
PanicButtonActivity.this, UpdateService.class));
} else {
toast.cancel();
toast.setText("Locked");
toast.show();
Context context = getApplicationContext();
KeyguardManager _guard = (KeyguardManager) context
.getSystemService(Context.KEyguard_SERVICE);
KeyguardLock _keyguardLock = _guard
.newKeyguardLock("KeyguardLockWrapper");
_keyguardLock.reenableKeyguard();
Log.i("Locked", "else");
PanicButtonActivity.this.stopService(new Intent(PanicButtonActivity.this,
UpdateService.class));
}
}
});
Receiver.java:
public class Receiver extends broadcastReceiver {
private boolean screenOff;
@Override
public void onReceive(Context context, Intent intent) {
if (intent.getAction().equals(Intent.ACTION_SCREEN_OFF)) {
screenOff = true;
} else if (intent.getAction().equals(Intent.ACTION_SCREEN_ON)) {
screenOff = false;
}
Intent i = new Intent(context, UpdateService.class);
i.putExtra("screen_state", screenOff);
context.startService(i);
}
}
服务:
public class UpdateService extends Service {
broadcastReceiver mReceiver;
@Override
public void onCreate() {
super.onCreate();
// register receiver that handles screen on and screen off logic
IntentFilter filter = new IntentFilter(Intent.ACTION_SCREEN_ON);
filter.addAction(Intent.ACTION_SCREEN_OFF);
mReceiver = new Receiver();
registerReceiver(mReceiver, filter);
}
@Override
public void onDestroy() {
unregisterReceiver(mReceiver);
Log.i("onDestroy Reciever", "Called");
super.onDestroy();
}
@Override
public void onStart(Intent intent, int startId) {
boolean screenOn = intent.getBooleanExtra("screen_state", false);
if (!screenOn) {
Log.i("screenON", "Called");
Toast.makeText(getApplicationContext(), "Awake", Toast.LENGTH_LONG)
.show();
} else {
Log.i("screenOFF", "Called");
}
}
@Override
public IBinder onBind(Intent intent) {
// Todo Auto-generated method stub
return null;
}
}
的Manifest.xml: –
<uses-sdk
android:minSdkVersion="8"
android:targetSdkVersion="19" />
<uses-permission android:name="android.permission.disABLE_KEyguard"/>
<application
android:allowBackup="true"
android:icon="@drawable/ic_launcher"
android:label="@string/app_name"
android:theme="@style/AppTheme" >
<activity
android:name="com.panic.app.PanicButtonActivity"
android:label="@string/app_name" >
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
<receiver android:name="com.panic.app.Receiver" />
<service android:name="com.panic.app.UpdateService" />
</application>
解决方法:
首先,与其他广泛的铸造intentsso不同,您需要制作一个将继续运行的服务:
public static class UpdateService extends Service {
@Override
public void onCreate() {
super.onCreate();
// register receiver that handles screen on and screen off logic
IntentFilter filter = new IntentFilter(Intent.ACTION_SCREEN_ON);
filter.addAction(Intent.ACTION_SCREEN_OFF);
broadcastReceiver mReceiver = new Receiver();
registerReceiver(mReceiver, filter);
}
@Override
public void onStart(Intent intent, int startId) {
boolean screenOn = intent.getBooleanExtra("screen_state", false);
if (!screenOn) {
// your code
} else {
// your code
}
}
}
你的接收器可以是某种东西
public class Receiver extends broadcastReceiver {
private boolean screenOff;
@Override
public void onReceive(Context context, Intent intent) {
if (intent.getAction().equals(Intent.ACTION_SCREEN_OFF)) {
screenOff = true;
} else if (intent.getAction().equals(Intent.ACTION_SCREEN_ON)) {
screenOff = false;
}
Intent i = new Intent(context, UpdateService.class);
i.putExtra("screen_state", screenOff);
context.startService(i);
}
}