javascript – Grid.Mvc.Ajax扩展网格初始化

嗨,我对使用JQuery& amp;的Web GUI dev非常陌生. Ajax和我正在尝试使用nuget包Grid.MVC.Ajax工作.自述文件陈述如下:

Follow thse steps to use Grid.Mvc.Ajax

1. Include ~/Scripts/gridmvc-ext.js after your ~/Scripts/grimvc.js include.

2. Include ~/Content/ladda-bootstrap/ladda-themeless.min.css CSS after your Bootstrap CSS/LESS include.

3. Include Ladda-bootstrap Javascript via the ~/Scripts/ladda-bootstrap/ladda.min.js
 and ~/Scripts/ladda-bootstrap/spin.min.js.

4. Create a view model for you grid data, for example:
public Person
{
   public string FirstName { get; set; }
   public string LastName { get; set; }
}

5. Add a Razor partial view for your grid data that uses an AjaxGrid<T> as the model type, 
Where T is your view model type:

@using GridMvc.Html
@using GridMvc.sorting
@model Grid.Mvc.Ajax.GridExtensions.AjaxGrid<Models.Person>

@Html.Grid(Model).Columns(columns =>
    {
      columns.Add(c => c.FirstName);
      columns.Add(c => c.LastName);
    }).sortable(true).WithPaging(10)

6. Add a controller action to retrieve the data for the first page of data that includes the Ajax pager HTML:

 public JsonResult Persons()
        {
            var vm = new List<Person>()
            {
                new Person() { FirstName = "John", LastName = "Doe" }
            }
            .AsQueryable();
            var ajaxGridFactory = new Grid.Mvc.Ajax.GridExtensions.AjaxGridFactory();
            var grid = ajaxGridFactory.CreateAjaxGrid(vm, 1, false);
        }

7. Add a controller action to retrieve data for paged items that returns a JsonResult without the Ajax page HTML:

 public JsonResult PersonsPaged(int page)
        {
            var vm = new List<Person>()
            {
                new Person() { FirstName = "John", LastName = "Doe" }
            }
            .AsQueryable();
            var ajaxGridFactory = new Grid.Mvc.Ajax.GridExtensions.AjaxGridFactory();
            var grid = ajaxGridFactory.CreateAjaxGrid(vm, page, true);
        }

8. Call the ajaxify Grid.Mvc.Ajax JavaScript plug-in method setting the non-paged and paged controller actions and optionally a form
to apply additional filtering to the grid. All input and select elements in the given form will be passed into your paged and non-paged controller actions:

 $(".grid-mvc").gridmvc().ajaxify({
                getPagedData: '/Home/Persons',
                getData : '/Home/PersonsPaged',
                gridFilterForm: $("#gridFilters")
            });

我按照说明进行了设置,但是我在第8步遇到了问题.因为我不确定如何调用JavaScript代码来填充网格.我已将上述内容包含在$(document).ready调用中,但这似乎不起作用:-(任何帮助都会非常感激.谢谢

解决方法:

您有两个选项:loadPage和refreshFullPage

这将调用您的PersonsPaged方法

$(".grid-mvc")
   .gridmvc()
   .loadPage()

这将调用你的人员方法.

$(".grid-mvc")
   .gridmvc()
   .refreshFullGrid()

此外,在您的Persons和PersonsPaged中,您可以返回如下的JSON:

public ActionResult Persons()
{
    var vm = new List<Person>()
    {
        new Person() { FirstName = "John", LastName = "Doe" }
    }.AsQueryable();

    var ajaxGridFactory = new AjaxGridFactory();
    var grid = ajaxGridFactory.CreateAjaxGrid(vm, 1, false);

    return Json(new { Html = grid.ToJson("_YourPartialWithGridCode", this), grid.HasItems },JsonRequestBehavior.AllowGet);
}

相关文章

IE6是一个非常老旧的网页浏览器,虽然现在很少人再使用它,但...
PHP中的count()函数是用来计算数组或容器中元素的个数。这个...
使用 AJAX(Asynchronous JavaScript and XML)技术可以在不...
Ajax(Asynchronous JavaScript and XML)是一种用于改进网页...
本文将介绍如何通过AJAX下载Excel文件流。通过AJAX,我们可以...
Ajax是一种用于客户端和服务器之间的异步通信技术。通过Ajax...