Ajax中如何向服务器发送XML文件

自己在学习时，会根据资料写一些小例子，希望自己在快淡忘的时候拿出来看看，重新唤起我的记忆

1.postingXML.html代码

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
  "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title>Sending an XML Request</title>

<script type="text/javascript">

var xmlHttp;

function createXMLHttpRequest() {
    if (window.ActiveXObject) {
        xmlHttp = new ActiveXObject("Microsoft.XMLHTTP");
    } 
    else if (window.XMLHttpRequest) {
        xmlHttp = new XMLHttpRequest();
    }
}
    
function createXML() {
    var xml = "<pets>";
    
    var options = document.getElementById("petTypes").childNodes;
    var option = null;
    for(var i = 0; i < options.length; i++) {
        option = options[i];
        if(option.selected) {
            xml = xml + "<type>" + option.value + "<\/type>";
        }
    }
    
    xml = xml + "<\/pets>";
    return xml;
}

function sendPetTypes() {
    createXMLHttpRequest();
    
    var xml = createXML();
    var url = "PostingXMLExample?timeStamp=" + new Date().getTime();
    
    xmlHttp.open("POST",url,true);
    xmlHttp.onreadystatechange = handleStateChange;
    xmlHttp.setRequestHeader("Content-Type","application/x-www-form-urlencoded");    
    xmlHttp.send(xml);
}
    
function handleStateChange() {
    if(xmlHttp.readyState == 4) {
        if(xmlHttp.status == 200) {
            parseResults();
        }
    }
}

function parseResults() {
    var responseDiv = document.getElementById("serverResponse");
    if(responseDiv.hasChildNodes()) {
        responseDiv.removeChild(responseDiv.childNodes[0]);
    }
    
    var responseText = document.createTextNode(xmlHttp.responseText);
    responseDiv.appendChild(responseText);
}


</script>
</head>

<body>
  <h1>Select the types of pets in your home:</h1>
  
  <form action="#">
    <select id="petTypes" size="6" multiple="true">
        <option value="cats">Cats</option>
        <option value="dogs">Dogs</option>
        <option value="fish">Fish</option>
        <option value="birds">Birds</option>
        <option value="hamsters">Hamsters</option>
        <option value="rabbits">Rabbits</option>
    </select>
    
    <br/><br/>
    <input type="button" value="Submit Pets" onclick="sendPetTypes();"/>
  </form>

  <h2>Server Response:</h2>

  <div id="serverResponse"></div>

</body>
</html>

2.PostingXMLExample.java

package com.wch.ajax.servlet;

import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import org.w3c.dom.Document;
import org.w3c.dom.NodeList;
import org.xml.sax.SAXException;

public class PostingXMLExample extends HttpServlet {
    
    protected void doPost(HttpServletRequest request,HttpServletResponse response)
    throws ServletException,IOException {
        
        String xml = readXMLFromRequestBody(request);
        Document xmlDoc = null;
        try {
            xmlDoc = 
                    DocumentBuilderFactory.newInstance().newDocumentBuilder()
                    .parse(new ByteArrayInputStream(xml.getBytes()));
        }
        catch(ParserConfigurationException e) {
            System.out.println("ParserConfigurationException: " + e);
        }
        catch(SAXException e) {
            System.out.println("SAXException: " + e);
        }

        /* Note how the Java implementation of the W3C DOM has the same methods
         * as the JavaScript implementation,such as getElementsByTagName and 
         * getNodeValue.
         */
        NodeList selectedPetTypes = xmlDoc.getElementsByTagName("type");
        String type = null;
        String responseText = "Selected Pets: ";
        for(int i = 0; i < selectedPetTypes.getLength(); i++) {
           type = selectedPetTypes.item(i).getFirstChild().getNodeValue();
           responseText = responseText + " " + type;
        }
        
        response.setContentType("text/xml");
        response.getWriter().print(responseText);
    }
    
    private String readXMLFromRequestBody(HttpServletRequest request){
        StringBuffer xml = new StringBuffer();
        String line = null;
        try {
            BufferedReader reader = request.getReader();
            while((line = reader.readLine()) != null) {
                xml.append(line);
            }
        }
        catch(Exception e) {
            System.out.println("Error reading XML: " + e.toString());
        }
        return xml.toString();
    }
}

Ajax中如何向服务器发送XML文件

自己在学习时，会根据资料写一些小例子，希望自己在快淡忘的时候拿出来看看，重新唤起我的记忆

1.postingXML.html代码

2.PostingXMLExample.java

3.配置文件web.xml

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