我们在周末侵入了我们的服务器,我正试图追踪入侵者的踪迹.它们似乎运行了一个perl脚本,导致名为init的www数据进程以100％运行.不幸的是我没有perl专业知识,所以我不知道这是做什么的：
6 my $processo =("atd","sendmail: accepting connections","rpc.idmapd","syslogd -m 0","/sbin/udevd -d","/sbin/init");
# ...
24 use IO::Socket;
25 use Socket;
26 use IO::Select;
27 chdir("/tmp");
28 $servidor="$ARGV[0]" if $ARGV[0];
29 $0="$processo"."\0"x16;;
30 my $pid=fork;
31 exit if $pid;
在我看来,第29行的指令旨在以某种方式隐藏过程.它究竟做了什么？
解决方法
从
perldoc perlvar开始：
On some (but not all) operating systems assigning to
$0modifies the argument area that thepsprogram sees. On some platforms you may
have to use specialpsoptions or a differentpsto see the changes.
Modifying the$0is more useful as a way of indicating the current
program state than it is for hiding the program you’re running.
所以是的,你的断言是正确的.它正在寻找掩盖它在ps中的显示方式.
